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5y^2-30y-40=0
a = 5; b = -30; c = -40;
Δ = b2-4ac
Δ = -302-4·5·(-40)
Δ = 1700
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1700}=\sqrt{100*17}=\sqrt{100}*\sqrt{17}=10\sqrt{17}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-10\sqrt{17}}{2*5}=\frac{30-10\sqrt{17}}{10} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+10\sqrt{17}}{2*5}=\frac{30+10\sqrt{17}}{10} $
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